Kshitij Singh answered . 2024-05-20 10:02:59
If you want all of them in an array (which might be too large if the number of digits is too large), you can use
n = number of digits b = range of the digits (0 to b) result = dec2base(0:(b+1)^n-1,b+1);
This will give you a character array since the digits might be bigger than 9.
If b is 9 or less, you can turn this into numeric with
result = dec2base(0:(b+1)^n-1,b+1) - '0';
Otherwise, you would need code to convert the letters 'A' - whatever into numbers.
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