y = filter(b,a,u);
%reading (durata)seconds of my file
info = audioinfo(filename_formato);
[y, Fs] = audioread(filename_formato,[1 info.SampleRate * durata]);
ns = size(y,1);
ts = 1/Fs;
%generating time vector
t = linspace(0,ts*ns,ns);
%designing the filter (let's say Fs = 44100Hz, fstop = 1000Hz)
[z,p,k] = ellip(6,0.5,20,fstop/Fs*2);
[b,a] = zp2tf(G.Z{1,1},G.P{1,1},G.K);
y = filter(b,a,u);
Neeta Dsouza answered . 2024-05-17 21:44:27
I am assuming you are using MATLAB 2019b. The above issue can be due to linspace. It is generating indices which are not integers (due to numerical approximation errors) and this made matrix indexing fail. You can verify this yourself, if you run the following code in MATLAB R2019b or later:
x = -50:1:50; y = linspace(-50,50,101); % Verify that result is different isequal(x,y) % Show that this makes indexing fail indices = y + 51; A = [1:1000]; B = A(indices);
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