Kindly help me to convert this into local date format

Question

How i can convert the list of date/time in to my local date format and let me know which format is it? Example: From 1992.752225 1992.765914 1992.779603 ................2018.460643 to dd/mm/yyyy or 'dd-mm-yyyy HH:MM:SS'

John Williams · Accepted Answer

d = [1992.752225; 1992.765914; 1992.779603; 2018.460643];
datetime(floor(d), 1, 1) + years(mod(d,1))





ans = 4&times;1 datetime array
01-Oct-1992 17:52:08 06-Oct-1992 17:51:51 11-Oct-1992 17:51:34 18-Jun-2018 05:54:49





However, I would be concerned about the difference between years() -- which uses fixed-length years -- and calendar years.
 
fd = floor(d);
datetime(fd, 1, 1) + (d-fd) .* days(365+leapyear(fd))





ans = 4&times;1 datetime array
02-Oct-1992 07:32:39 07-Oct-1992 07:47:18 12-Oct-1992 08:01:57 18-Jun-2018 03:13:57





The similarities of the first three times in the first version suggest to me that the time system is using fixed length years --- but that can make it difficult to figure out how to handle the leapyear. Some time systems like that just remove the leap day; if you are using one of those then for entries for which leapyear() is true and the date is after Feb 28, you have to add one day.

Kindly help me to convert this into local date format

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