How can I draw a chart of the average power versus the distance, as in the following figure for knowledge that the value of the average power (1 * 101), i.e. a matrix, and the distance between the light source and the light receiver is 3 meters Assuming average power = Paver Distance = h
Kshitij Singh answered .
2025-11-20
To plot the average power versus distance, you need to have a relationship between the average power PavgP_{\text{avg}} and the distance hh (which is the distance between the light source and the receiver). In general, the power of a signal (like optical power) tends to decay with distance, and this relationship can often be modeled using an inverse-square law or some other specific decay model depending on the type of system you're dealing with.
Let's assume you want to model the optical power decay with distance, which can follow an inverse-square law:
Pavg(h)=P0h2P_{\text{avg}}(h) = \frac{P_0}{h^2}
where:
In your case, you can generate a series of distances (say from 1 meter to 10 meters), calculate the corresponding powers using the inverse-square law, and plot the result.
% Parameters
P0 = 1e11; % Initial power (example, you can adjust this)
h_values = 1:0.1:10; % Range of distances from 1m to 10m (can adjust as needed)
% Calculate average power based on inverse square law
P_avg = P0 ./ h_values.^2; % Inverse-square law
% Plotting the result
figure;
plot(h_values, P_avg, '-o');
xlabel('Distance (m)');
ylabel('Average Power (P_{avg})');
title('Average Power vs Distance (Inverse-Square Law)');
grid on;
Parameters:
P0 is the initial power at h=1h = 1 meter (or a reference distance of your choice).h_values is the array of distances over which you want to plot the power.Power Calculation:
Plotting:
plot function is used to visualize the average power against the distance, with appropriate labels and a grid for clarity.