Question
hi, I was designing a neural network using the app in Matlab and I the MSE (mean squared error)that I got in the training set is 100-200. I don't have any more data to improve the network. So, should I go forward with the network or improve it in any other way?
Expert Answer
John Williams
PhD Expert
Answered Sep 12, 2026
Impossible to tell without knowing or being able to calculate the normalized degree-of-freedom-adjusted (DOFA) training subset MSE (NMSEtrna) or the corresponding Rsquare or coefficient of determination (Rsqtrna = 1-NMSEtrna).
Search Rsquare and "coefficient of determination" on Google and Wikipedia.
Calculations can be made as follows
[ I N ] = size(x) [ O N ] = size(t) = size(y) Ntrn = No. of training examples ( Ntrn ~ 0.7*N is default ) Ntrneq = Ntrn*O % No. of training equations MSEtrn00 = mean(var(ttrn',1))% avg training target variance SSEtrn = sse(ttrn-ytrn) MSEtrn = SSEtrn/Ntrneq NMSEtrn = MSEtrn/MSEtrn00 Rsqtrn = 1 - NMSEtrn
Adjustments ("a") for degrees of freedom lost when evaluating the net with the same data that was used to estimate the weights:
H = number of hidden nodes Nw = (I+1)*H+(H+1)*O % No. of unknown weights Ndof = Ntrneq - Nw % No. of DOF MSEtrn00a = mean(var(ttrn',0))
NOTE: If there are more unknown weights than equations, Ndof < 0 and special methods like trainbr and/or regularization are required. Otherwise,
For DOFA with Ndof > 0:
MSEtrna = SSEtrn/Ndof NMSEtrna = MSEtrna/MSEtrn00a Rsqtrna = 1 - NMSEtrna
For many problems an appropriate training goal is
R2sqtrna >= 0.99
or
MSEtrn <= MSEtrngoal = 0.01*max(Ndof,0)*MSEtrn00a/Ntrneq
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