close all clc
%%wieght constraining
cont=0;
weight=zeros(1,4);
for weight1=0:0.01:0.28
for weight2=0:0.01:0.28
for weight3=0:0.01:0.28
for weight4=0:0.01:0.28
check =(weight1^2+weight2^2+weight3^2+weight4^2);
if check == 0.25
cont= cont+1;
weight(cont,:)=[weight1,weight2,weight3,weight4];
end
end
end
end
end
Prashant Kumar answered . 2024-05-17 20:01:19
As pointed out by @John in the comments, you are getting this error because of finite precision of floating point numbers in the computer systems. A way around this is to compare numbers with tolerance. To do that here is one option, replace
if check == 0.25
with
if ismembertol(check, 0.25, 1e-6)
the third number to ismembertol() is the tolerance value i.e. how much difference from 0.25 on the left side of comparison will be considered equal to 0.25. For your code, this gives following a total of 13 combinations of weights
weight =
0.1600 0.2600 0.2800 0.2800
0.1600 0.2800 0.2600 0.2800
0.1600 0.2800 0.2800 0.2600
0.2500 0.2500 0.2500 0.2500
0.2600 0.1600 0.2800 0.2800
0.2600 0.2800 0.1600 0.2800
0.2600 0.2800 0.2800 0.1600
0.2800 0.1600 0.2600 0.2800
0.2800 0.1600 0.2800 0.2600
0.2800 0.2600 0.1600 0.2800
0.2800 0.2600 0.2800 0.1600
0.2800 0.2800 0.1600 0.2600
0.2800 0.2800 0.2600 0.1600
If you increase the tolerance
if ismembertol(check, 0.25, 1e-3)
then even more elements will satisfy the equality. 1e-3 gives 61 points
weight =
0.1600 0.2600 0.2800 0.2800
0.1600 0.2700 0.2700 0.2800
0.1600 0.2700 0.2800 0.2700
0.1600 0.2800 0.2600 0.2800
0.1600 0.2800 0.2700 0.2700
0.1600 0.2800 0.2800 0.2600
0.1900 0.2500 0.2700 0.2800
0.1900 0.2500 0.2800 0.2700
0.1900 0.2700 0.2500 0.2800
0.1900 0.2700 0.2800 0.2500
0.1900 0.2800 0.2500 0.2700
0.1900 0.2800 0.2700 0.2500
0.2400 0.2500 0.2500 0.2600
0.2400 0.2500 0.2600 0.2500
0.2400 0.2600 0.2500 0.2500
0.2500 0.1900 0.2700 0.2800
0.2500 0.1900 0.2800 0.2700
0.2500 0.2400 0.2500 0.2600
0.2500 0.2400 0.2600 0.2500
0.2500 0.2500 0.2400 0.2600
0.2500 0.2500 0.2500 0.2500
0.2500 0.2500 0.2600 0.2400
0.2500 0.2600 0.2400 0.2500
0.2500 0.2600 0.2500 0.2400
0.2500 0.2700 0.1900 0.2800
0.2500 0.2700 0.2800 0.1900
0.2500 0.2800 0.1900 0.2700
0.2500 0.2800 0.2700 0.1900
0.2600 0.1600 0.2800 0.2800
0.2600 0.2400 0.2500 0.2500
0.2600 0.2500 0.2400 0.2500
0.2600 0.2500 0.2500 0.2400
0.2600 0.2800 0.1600 0.2800
0.2600 0.2800 0.2800 0.1600
0.2700 0.1600 0.2700 0.2800
0.2700 0.1600 0.2800 0.2700
0.2700 0.1900 0.2500 0.2800
0.2700 0.1900 0.2800 0.2500
0.2700 0.2500 0.1900 0.2800
0.2700 0.2500 0.2800 0.1900
0.2700 0.2700 0.1600 0.2800
0.2700 0.2700 0.2800 0.1600
0.2700 0.2800 0.1600 0.2700
0.2700 0.2800 0.1900 0.2500
0.2700 0.2800 0.2500 0.1900
0.2700 0.2800 0.2700 0.1600
0.2800 0.1600 0.2600 0.2800
0.2800 0.1600 0.2700 0.2700
0.2800 0.1600 0.2800 0.2600
0.2800 0.1900 0.2500 0.2700
0.2800 0.1900 0.2700 0.2500
0.2800 0.2500 0.1900 0.2700
0.2800 0.2500 0.2700 0.1900
0.2800 0.2600 0.1600 0.2800
0.2800 0.2600 0.2800 0.1600
0.2800 0.2700 0.1600 0.2700
0.2800 0.2700 0.1900 0.2500
0.2800 0.2700 0.2500 0.1900
0.2800 0.2700 0.2700 0.1600
0.2800 0.2800 0.1600 0.2600
0.2800 0.2800 0.2600 0.1600
So it depends on how much tolerance is acceptable for your problem.
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