p1=[-83.3958 12.4263 36.4348]; p2=[-86.9626 21.0892 23.2980]; p3=[ -274.7046 58.9844 -171.2332]; v1 = p2-p1; v2 = p3-p2; angle = rad2deg(atan2(norm(cross(v1,v2)),dot(v1,v2)));
I see in other forums, but none have a explain how to calculate the three angles of one vector relative to a another. Thanks in advance.
Kshitij Singh answered . 2024-05-17 21:29:43
I think you should project the vectors onto each plane consecutively and calculate then the angle formed by the projections:
p1=[-83.3958 12.4263 36.4348]; p2=[-86.9626 21.0892 23.2980]; p3=[ -274.7046 58.9844 -171.2332]; v1 = p2-p1; v2 = p3-p2; v_1 = [v1(1) v1(2)]; v_2 = [v2(1) v2(2)]; ang1 = acos(dot(v_1,v_2)/(norm(v_1)*norm(v_2))); v_1 = [v1(2) v1(3)]; v_2 = [v2(2) v2(3)]; ang2 = acos(dot(v_1,v_2)/(norm(v_1)*norm(v_2))); v_1 = [v1(1) v1(3)]; v_2 = [v2(1) v1(3)]; ang3 = acos(dot(v_1,v_2)/(norm(v_1)*norm(v_2)));
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