Random number generation from uniform distribution
Good afternoon, I'm currently trying to generate random numbers from a uniform distribution, but I'm not sure how to input probabilities. For example, Let S be uniformly distributed between 70 and 130: a=70; b=130; S=a+(b-a).*rand However, let's say we want to generate T which is uniformly distributed: between 0.1 and 1.0 (with probability 0.75) between 1.0 and 5.0 (with probability 0.25) Is it possible to use the rand function as normal? i.e. a=0.1; b=1.0; c=5.0 T=([a+(b-a).*rand]*0.75)+([b+(c-b).*rand]*0.25) I appreciate any feedback.
Kshitij Singh answered .
2025-11-20
N = 1000000; a=0.1; b=1.0; c=5.0; r1 = rand(N,1); r2 = rand(N,1); T=(a+(b-a).*r1).*(r2<=0.75) + (b+(c-b).*r1).*(r2>0.75); figure hist(T,0.105:0.01:4.995)