So from 0
John Williams answered .
2025-11-20
Z=@(x) 1.25*((0.72*(x/5))-((x/5).^2)).*(x>0 & x<1.8)+...
(1125/1024)*((0.28+(0.72*(x/5)))-((x/5).^2)).*(x>1.8 & x<5);